面白い気がする等式
1.
$x^4+y^4+(x+y)^4=2(x^2+xy+y^2)^2$
2.
$1/(1-x)+1/(1-1/x)=1$
3.
$x^4-6*x^2+1=(x^2-1)^2-4*x^2=(x^2+2*x-1)*(x^2-2*x-1)$
4.
$1/x1+1/x2+1/x3-1/(x1+x2+x3)=(x1+x2)*(x2+x3)*(x3+x1)/(x1*x2*x3*(x1+x2+x3))$
1.
$x^4+y^4+(x+y)^4=2(x^2+xy+y^2)^2$
2.
$1/(1-x)+1/(1-1/x)=1$
3.
$x^4-6*x^2+1=(x^2-1)^2-4*x^2=(x^2+2*x-1)*(x^2-2*x-1)$
4.
$1/x1+1/x2+1/x3-1/(x1+x2+x3)=(x1+x2)*(x2+x3)*(x3+x1)/(x1*x2*x3*(x1+x2+x3))$